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• You can see it in manga! Fate/Grand Order(1) Liyo, TYPE-MOON (Written by)KADOKAWA (Publishing House) / Kadokawa Digital ComicsAugust 2, 2017 (Release date)Kindle version (Format) Gather in this realm, O spirits of the unjust of one hundred million husbands, even if they are incompatible enemies, now leave each other's backs My real name is Joan of Arc I will be your shield in the name of the Lord I'm sorry I cried because I was moved by my lines It's too cool (p.6) Cheating sheet lol。Don't skip it from the beginning。I think Olga Marie is cute。Joan of Arc and Kashiwa Mochi。Altera is cute。The main character on the cover is sexy。
• Chart Formula Mathematics 1 part2 [Equations and Inequality]    Toshikazu Sunada (Written by) Zuken Publishing Co., Ltd. (Publishing House) 2003April 1, 2016 (Release date) Hardcover (Format) 今日も進めていきます。 今回は問4からだ。 式を因数分解せよということで(1)-(10)まで式が10題並んでいる。 面倒だが計算するか。 (6)、(9)では以下の公式を使った。 $${ \left( a+b \right) }^{ 3 }={ a }^{ 3 }+3{ a }^{ 2 }b+3a{ B }^{ 2 }+{ B }^{ 3 }$$ $${ \left( a-b \right) }^{ 3 }={ a }^{ 3 }-3{ a }^{ 2 }b+3a{ B }^{ 2 }-{ B }^{ 3 }$$ $${ a }^{ 3 }+{ B }^{ 3 }=\left( a+b \right) \left( { a }^{ 2 }-ab+{ B }^{ 2 } \right) $$ $${ a }^{ 3 }-{ B }^{ 3 }=\left( a-b \right) \left( { a }^{ 2…
• Chart Equation Mathematics 1 Part1 [Equations and Inetheles]    Toshikazu Sunada (Written by) Zuken Publishing Co., Ltd. (Publishing House) 2003April 1, 2016 (Release date) Hardcover (Format) Good、I'm going to start this collection of questions today~。 Let's start with Chapter 1, "Equations and Inequalities"。 Question 1、It is said that it is a problem of Doshisha Women's University。 This is just a matter of expanding the expression。 It's a hassle to calculate.。 \({ x }^{ 5 }\)The coefficient of is (-19\)、\({ x }^{ 3 }\)The coefficient of is (-23\)だろう。 ほい、正解～。 According to the commentary、全部を展開しなくてもその次数の項にだけ注目すればいいみたい、I see。 次は第2問。 同志社大の問題だ。 (1)は条件式から $$xyz=3\left( xy+yz+xz \right)\tag{1} $$ となり、あとは普通に与えられた式を展開して(1)式を代入すれば、都合よく\(\left( xy+yz+xz \right)\)section disappears and the answer comes out。 (2)According to the hint、 $${ x }^{ 3 }+{ y }^{ 3 }+{ z }^{ 3 }-3xyz=left( x+y+z right) \left( { x }^{ 2 }+{ y }^{ 2 }+{ z }^{ 2 }-xy-yz-zx right) $$ It seems to use the formula that。 If we transform this equation into、 $${ x }^{ 3 }+{ y }^{ 3 }+{ z }^{ 3 }={ \left( x+y+z right) }^{ 3 }-3\left( x+y+z right) \left( xy+yz+zx \right) +3xyz $$ このようになって、The rest(1)と同様に式を代入すれば\({ x }^{ 3…