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• Chart Type Mathematics A part2 [Several In Case] Takaaki Yanagawa (Written by)Zuken Publishing Co., Ltd. (Publishing House)2003April 1, 2016 (Release date)Hardcover (Format) 今日も場合の数の問題を解いていくぞ～問6からだ。Oh well、It's a matter of combinations and circular permuting.。Different(n\)個のものの円順列の総数は\(\left( n-1 \right) !\)represented by。You can use this to solve it.。 And question 7。I made a mistake in this problem.。(1)、(2)Both、simply right four、I calculated it as a permutable to sort the top four.。By the way、Permutables that contain the same are represented by the following formula:。\(n\)Out of 10、同じものがそれぞれ\(p\)Pieces、\(q\)Pieces、\(r\)When there is one、これらを\(n\)What is the total number of permutables to be arranged?、 $${ _{ n }{ C }_{ P }\times }{ _{ n-p }{ C }_{ q }\times }{ _{ n-p-q }{ C }_{ r }=\frac { n! }{ P!q!r! } }\quad \left( p+q+r=n \right) $$ But、Now we're going to find a rectangular path.。This route is in the shape of a triangle.。 According to the answer example(1)3 squares sideways as a temporary road、Think of a three-square-length rectangular path。And、Point C、D、E、They set an F。And then、The path from point C to point D is right 3.、Because it is a permuting of the top three、it's officially required earlier。The rest is an extra route.、(Route through point E)\(+\)(Route through point F)\(-\)(Path through points E and F together)seeking as、It's good to pull.。Hmm.、I see. (2)It's hard to do it all the time.。Point P according to the answer example、Q、R、Establish S。and divided in the following four cases。 Pを通る経路 Qを通り、Pを通る経路 Rを通り、Qを通らない経路 Sを通り、Rを通らない経路 このようにすると、They are so、It's like it counts without duplication.。I didn't know this.。If the problem of such a route is focused on which point to pass, should it be parted?。 Next is Question 8.。6It's a matter of how to get on a boat that can take up to four people.。When distinguishing people、If you don't and you want to distinguish a boat、ask for four combinations if you don't。(1)if you don't distinguish between people and boats.、Only the number of people who share as hinted at is a problem.。(4)The (3)\(\div 2!\)It's like it's to。I solved it by the case、The answer became the same.。Well, I guess that's the way it is.。 Next is Question 9.。(1)is a matter of simple combinations。But、As for me(2)、(3)I made this wrong again.。"Is it a duplicate combination problem?" I thought, "I'm not going to do that."、It was a duplicate permuting problem.。ちなみに重複組合せで\(n\)個の異なるものから重複を許して\(r\)個をとる組合せの数は\({ _{ n+r-1 }{ C }_{ r } }\)represented by。\(n-1\)個の仕切りと\(r\)it's the number of permutings of 0 pieces.。Duplicate permuting, on the other hand,、Different(n\)個のものから重複を許して\(r\)In permuting to take out the pieces、\({ n }^{ r }\)required in。(2)It's easy to use.、(3)even if you're not(2)If you pull from, you will be asked。分からなかったな～ 最後に問10。It's a binary theorem problem.。二項定理とは\({ \left( a+b \right) }^{ n }\)の展開式の一般項（第r+1番目の項）が\({ _{ n }{ C }_{ r } }{ a }^{ n-r }{ B }^{ r }\)is to be written with。(1)You can use this to solve it.。(2)According to the hint, it seems to be good as follows。\({ x }^{ k }\)の係数を\({ a }_{ k }\)They go to。そして\(\frac…
• National Geographic Japan March 2019 ナショナル ジオグラフィック(Edit)日経ナショナルジオグラフィック社 (Publishing House)2019年2月28日 (Release date)Magazine (Format) 今月号は忙しくて読んでいない。今回のテーマは地球外生命探査、ロンドンについてとか。今や地球外生命体がいるのは間違いなく、どうやって見つけるかが問題らしい。新しい技術も開発されていて夢が膨らむ。ロンドンの街についても書かれていた。ロンドン ザ・シャード、キングス・クロス地区、キューガーデン、クロスレール、子午線の庭など、僕も一度訪れてみたい。フリーソロというロッククライミングの競技も取り上げられていたが、とても危険で事前の準備が大事と思った。
• I、Beautiful? Popup (Written by)Wikipedia (The free encyclopedia)1978In December (KIA elephant day)Myth (Classification) 風説データベース東京謎伝説うわごとのとなり発言小町国立国会図書館 Yahoo!JAPAN 知恵袋 噂の激震地かぁ。マスクの流行。